(2x^2-5x+4)/(x+1)

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Solution for (2x^2-5x+4)/(x+1) equation: 


D( x )

x+1 = 0

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x in (-oo:-1) U (-1:+oo)

(2*x^2-(5*x)+4)/(x+1) = 0

(2*x^2-5*x+4)/(x+1) = 0

2*x^2-5*x+4 = 0

2*x^2-5*x+4 = 0

DELTA = (-5)^2-(2*4*4)

DELTA = -7

DELTA < 0

1 = 0

1/(x+1) = 0

x belongs to the empty set

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